Series · 0606 Topic 12
Arithmetic Progressions
Written by Teacher Rig
8 years teaching IGCSE Add Math · Updated 12 June 2026
An arithmetic progression adds a constant difference each step: , , , … Test for it by subtracting consecutive terms, constant difference, AP confirmed.
The formulas
- nth term:
- Sum of n terms: or
All three memorised. The second sum form is criminally underused: when you know the last term (or can get it cheaply), halves the algebra.
The standard question: translate facts into equations
The 4th term of an AP is 14 and the sum of the first 10 terms is 185. Find and . ← translation line 1 (M) ← translation line 2 (M) Solve simultaneously: from the first, ,
Each given fact becomes exactly one equation, write the translations before solving, because they carry the method marks even if the algebra slips. The classic trap is the off-by-one: the 4th term uses , the 10th uses . Saying "" aloud as you substitute kills the error.
Other regulars: “which term equals 95?” → set , solve for (must come out a positive integer, if not, re-check); “how many terms are needed for the sum to exceed 1000?” → , a quadratic inequality in , answered with the integer that first qualifies.
Word-problem costumes
APs arrive dressed as salaries rising by a fixed annual increment, seats per row increasing by a constant, stacked logs. The detection question: is a constant amount added each step? (Constant ratio means a GP.) Define and explicitly from the story (” = first-year salary = 30 000, = 2 000”) before touching formulas, examiners credit the setup.
Common mistakes
- slips: computed with
- Sum and term formulas swapped
- from “which term” equations left as a fraction without alarm
- AP formulas applied to a sequence never tested for constant difference
- Word problems started without defining , , in the story’s terms
Full topic context: Series notes · the multiplicative twin: geometric progressions.