Quadratic Functions · 0606 Topic 2

Quadratic Inequalities

Teacher Rig, IGCSE Add Math tutor

Written by Teacher Rig

8 years teaching IGCSE Add Math · Updated 12 June 2026

To solve a quadratic inequality, never trust sign rules recited from memory, sketch. The method is three steps and it is essentially error-proof:

The method

Solve 2x25x302x^2 - 5x - 3 \ge 0.

  1. Roots: solve the equality. 2x25x3=0(2x+1)(x3)=0x=12,32x^2 - 5x - 3 = 0 \to (2x + 1)(x - 3) = 0 \to x = -\frac{1}{2}, 3
  2. Sketch: positive x2x^2 coefficient \to upward parabola crossing at 12-\frac{1}{2} and 33
  3. Read the region: "0\ge 0" means on or above the axis, the outer arms. x12x \le -\frac{1}{2} or x3x \ge 3

The factorising line and the sketch are both visible method; the final answer takes the marks only if the regions are right, which the sketch guarantees.

Writing the answer properly

  • Outside regions (>0> 0 with upward parabola): two separate inequalities joined by “or”, x12x \le -\frac{1}{2} or x3x \ge 3. The chained form "12x3-\frac{1}{2} \ge x \ge 3" is meaningless and scores nothing.
  • Inside region (<0< 0): one sandwich, 12<x<3-\frac{1}{2} < x < 3.
  • Strict vs non-strict follows the question’s symbol: \ge keeps the roots, >> excludes them.

A downward parabola (negative x2x^2 coefficient) flips which region is which, another reason the sketch beats memorised rules. Alternatively multiply through by 1-1 first and flip the inequality sign.

Where these inequalities ambush you

The most common 0606 appearance isn’t a standalone question, it’s the second half of a discriminant problem:

“Find the values of kk for which x2+kx+2k=0x^2 + kx + 2k = 0 has two distinct real roots.” b24ac>0b^2 - 4ac > 0: k28k>0k(k8)>0k^2 - 8k > 0 \to k(k - 8) > 0 \to sketch in kk \to k<0k < 0 or k>8k > 8

Students who can do both halves separately still lose marks by treating the kk-inequality as an equation and stopping at k=0,8k = 0, 8. The variable changed name; the method didn’t.

Common mistakes

  • Regions read without a sketch (the wrong-way-round answer)
  • Two-region answers chained into one impossible inequality
  • Roots included/excluded against the question’s symbol
  • Discriminant questions left as equalities
  • Dividing by a negative without flipping the sign

Full topic context: Quadratic Functions notes · cubic versions: solving cubic inequalities graphically.

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